Đáp án đúng: C
y = 3x.
$\begin{array}{l}2Fe{{(N{{O}_{3}})}_{2}}\xrightarrow{{{t}^{o}}}F{{e}_{2}}{{O}_{3}}+\frac{1}{2}{{O}_{2}}+\,4N{{O}_{2}}\\\,\,\,\,\,\,x\,mol\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\xrightarrow{{}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{x}{4}\,\,\,\,\,\,\to \,\,\,2x\\2Fe{{S}_{2}}+\frac{11}{2}{{O}_{2}}\xrightarrow{{}}F{{e}_{2}}{{O}_{3}}+4S{{O}_{2}}\\y\,mol\,\to \,\frac{11y}{4}\,\,\,\,\,\,\,\,\,\,\,\,\,\xrightarrow{{}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2y\end{array}$
Áp suất không đổi ⇒ số mol khí trong bình không đổi
$\Rightarrow \frac{11y}{4}=\frac{x}{4}+2x+2y\Rightarrow y=3x$