Đáp án đúng: B CrCl3. $\begin{array}{l}X:\,Cr{{(OH)}_{3}};\,\,\,Y:\,Cr{{(OH)}_{3}};\,\,Z:\,Cr(OH)_{4}^{-}\\Cr{{(OH)}_{3}}+3HCl\xrightarrow{{}}CrC{{l}_{3}}+3{{H}_{2}}O\\Cr(OH)_{4}^{-}+4HCl\xrightarrow{{}}CrC{{l}_{3}}+4{{H}_{2}}O+C{{l}^{-}}\end{array}$