Đáp án đúng: A
Ca.
$\begin{array}{l}\text{MC}{{\text{O}}_{\text{3}}}\,\xrightarrow{{{\text{t}}^{\text{o}}}}\,\text{MO}\,\text{+}\,\text{C}{{\text{O}}_{\text{2}}}\\{{\text{m}}_{\text{C}{{\text{O}}_{\text{2}}}}}\,\text{=}\,{{\text{m}}_{\text{MC}{{\text{O}}_{\text{3}}}}}\,\text{-}\,\,{{\text{m}}_{\text{MO}}}\,\text{=}\,\text{5,25}\,\text{-}\,\text{2,94}\,\,\text{=}\,\,\text{2,31}\,\text{gam}\\\Rightarrow {{\text{n}}_{\text{MC}{{\text{O}}_{\text{3}}}}}\,\text{=}\,{{\text{n}}_{\text{C}{{\text{O}}_{\text{2}}}}}\,\text{=}\,\text{0,0525}\,\text{mol}\\\Rightarrow \,{{\text{M}}_{\text{MC}{{\text{O}}_{\text{3}}}}}\,\text{=}\,\frac{\text{5,25}}{\text{0,0525}}\,\text{=}\,\text{100}\,\Rightarrow \,{{\text{M}}_{\text{M}}}\,\text{=}\,\text{40}\,\text{(Ca)}\end{array}$