Đáp án:
$\begin{array}{l}
e)\frac{z}{{2 + 3i}} - \left( {1 + 2i} \right) = 5 - 6i\\
\Rightarrow \frac{z}{{2 + 3i}} = 6 - 4i\\
\Rightarrow z = \left( {6 - 4i} \right).\left( {2 + 3i} \right)\\
\Rightarrow z = 12 + 12 + 18i - 8i\\
\Rightarrow z = 24 + 10i\\
f)2iz + 3 = 5z + 4\\
\Rightarrow \left( {2i - 5} \right)z = 1\\
\Rightarrow z = \frac{1}{{2i - 5}}\\
\Rightarrow z = \frac{{2i + 5}}{{\left( {2i - 5} \right)\left( {2i + 5} \right)}}\\
\Rightarrow z = \frac{{2i + 5}}{{ - 4 - 25}}\\
\Rightarrow z = - \frac{5}{{29}} - \frac{2}{{29}}i
\end{array}$
