Giải thích các bước giải:
\(\begin{array}{l}
\dfrac{{3z - 4y}}{5} = \dfrac{{5y - 3x}}{4} = \dfrac{{4x - 5z}}{3}\\
= \dfrac{{60z - 80y}}{{100}} = \dfrac{{80y - 48x}}{{64}} = \dfrac{{48x - 60z}}{{48}}\\
= \dfrac{{60z - 80y + 80y - 48x + 48x - 60z}}{{100 + 64 + 48}}\\
= 0\\
\Rightarrow 3z = 4y \Rightarrow \dfrac{z}{4} = \dfrac{y}{3}\\
5y = 3x \Rightarrow \dfrac{y}{3} = \dfrac{x}{5}\\
4x = 5z \Rightarrow \dfrac{x}{5} = \dfrac{z}{4} \Rightarrow \dfrac{{{x^2}}}{{25}} = \dfrac{{{z^2}}}{{16}} = \dfrac{{{x^2} - {z^2}}}{{25 - 16}} = \dfrac{{36}}{9} = 4\\
\Rightarrow {x^2} = 100 \Rightarrow x = \pm 10\\
{z^2} = 64 \Rightarrow z = \pm 8\\
\Rightarrow y = \pm 6
\end{array}\)
