Đáp án:
$\begin{array}{l}
+ ){\left( {2x - 3} \right)^2} - 4x\left( {x - 3} \right)\\
= 4{x^2} - 12x + 9 - 4{x^2} + 12x\\
= 9\\
+ )\frac{{5{x^3} - 10{x^2} + x - 2}}{{x - 2}}\\
= \frac{{5{x^2}\left( {x - 2} \right) + x - 2}}{{x - 2}}\\
= \frac{{\left( {x - 2} \right)\left( {5{x^2} + 1} \right)}}{{x - 2}}\\
= 5{x^2} + 1
\end{array}$