Đáp án:
18. B
19. 1D; 2A; 3C; 4B
20. A
Giải thích các bước giải:
Câu 18:
Ta có:
\(\begin{gathered}
{F_{hd}} = \frac{{G.{m_1}.{m_2}}}{{{r^2}}} = \frac{{G.{m^2}}}{{{r^2}}} \Rightarrow m = \sqrt {\frac{{{F_{hd}}.{r^2}}}{G}} \hfill \\
\Rightarrow m = \sqrt {\frac{{{{1,0672.10}^{ - 7}}{{.0,1}^2}}}{{{{6,67.10}^{ - 11}}}}} = 4kg \hfill \\
\end{gathered} \)
Câu 19:
1D; 2A; 3C; 4B
Câu 20:
Ta có:
\(\begin{gathered}
{F_{dh}} = k.\Delta l = k.\left| {l - {l_0}} \right| \hfill \\
\Rightarrow k = \frac{{{F_{dh}}}}{{\left| {l - {l_0}} \right|}} = \frac{{15}}{{\left| {0,22 - 0,2} \right|}} = 750N/m \hfill \\
\end{gathered} \)