Cho hình hộp $\displaystyle ABCD.{{A}_{1}}{{B}_{1}}{{C}_{1}}{{D}_{1}}$. Gọi$\displaystyle M$ là trung điểm$\displaystyle AD$. Chọn đẳng thức đúng.
A. $\displaystyle \overrightarrow{{{B}_{1}}M}=\overrightarrow{{{B}_{1}}B}+\overrightarrow{{{B}_{1}}{{A}_{1}}}+\overrightarrow{{{B}_{1}}{{C}_{1}}}$.
B. $\displaystyle \overrightarrow{{{C}_{1}}M}=\overrightarrow{{{C}_{1}}C}+\overrightarrow{{{C}_{1}}{{D}_{1}}}+\frac{1}{2}\overrightarrow{{{C}_{1}}{{B}_{1}}}$.
C. $\displaystyle \overrightarrow{{{C}_{1}}M}=\overrightarrow{{{C}_{1}}C}+\frac{1}{2}\overrightarrow{{{C}_{1}}{{D}_{1}}}+\frac{1}{2}\overrightarrow{{{C}_{1}}{{B}_{1}}}$.
D. $\overrightarrow{B{{B}_{1}}}+\overrightarrow{{{B}_{1}}{{A}_{1}}}+\overrightarrow{{{B}_{1}}{{C}_{1}}}=2\overrightarrow{{{B}_{1}}D}$.
A. $\displaystyle \overrightarrow{{{B}_{1}}M}=\overrightarrow{{{B}_{1}}B}+\overrightarrow{{{B}_{1}}{{A}_{1}}}+\overrightarrow{{{B}_{1}}{{C}_{1}}}$.
B. $\displaystyle \overrightarrow{{{C}_{1}}M}=\overrightarrow{{{C}_{1}}C}+\overrightarrow{{{C}_{1}}{{D}_{1}}}+\frac{1}{2}\overrightarrow{{{C}_{1}}{{B}_{1}}}$.
C. $\displaystyle \overrightarrow{{{C}_{1}}M}=\overrightarrow{{{C}_{1}}C}+\frac{1}{2}\overrightarrow{{{C}_{1}}{{D}_{1}}}+\frac{1}{2}\overrightarrow{{{C}_{1}}{{B}_{1}}}$.
D. $\overrightarrow{B{{B}_{1}}}+\overrightarrow{{{B}_{1}}{{A}_{1}}}+\overrightarrow{{{B}_{1}}{{C}_{1}}}=2\overrightarrow{{{B}_{1}}D}$.
Loga
Hóa Học lớp 12
