\(6^{x-2}\) :12 =3

\(6^{x-2}\) = 3.12

\(6^{x-2}\) = 36

\(6^{x-2}\) = \(6^2\)

⇒ x - 2 =2

x = 2+ 2

x = 4

Vậy x =4

3 + \(2^{x-1}\) = 24 - [\(4^2\) - (\(2^2\) -1)]

3 + \(2^{x-1}\) = 24 - [16 - (4-1)]

3 + \(2^{x-1}\) = 24 - (16 - 3)

3 + \(2^{x-1}\) = 24 - 13

3 + \(2^{x-1}\) = 11

\(2^{x-1}\) = 11-3

\(2^{x-1}\) = 8

\(2^{x-1}\) = \(2^3\)

⇒ x - 1 = 3

x = 3 + 1

x = 4

Vậy x = 4

\(\left(7x-11\right)^3\) = \(2^5.5^2+200\)

\(\left(7x-11\right)^3\)\(\left(7x-11\right)^3\)