Giải thích các bước giải:
$\dfrac{(x^2+6|x|+48)(x^2+12|x|+27)}{x^2}=675$
$+)x<0\to \frac{\left(x^2-6x+48\right)\left(x^2-12x+27\right)}{x^2}=675$
$\to \left(x^2-6x+48\right)\left(x^2-12x+27\right)=675x^2$
$\to x^4-18x^3-528x^2-738x+1296=0$
$\to x\approx \:1.00703\dots ,\:x\approx \:-2.60481\dots ,\:x\approx \:-14.49271\dots ,\:x\approx \:34.09049\dots $
$+)x>0\to \frac{\left(x^2+6x+48\right)\left(x^2+12x+27\right)}{x^2}=675$
$\to \left(x^2+6x+48\right)\left(x^2+12x+27\right)=675x^2$
$\to x\approx \:-1.00703\dots ,\:x\approx \:2.60481\dots ,\:x\approx \:14.49271\dots ,\:x\approx \:-34.09049\dots $
