Đáp án đúng: B
4,5M
NO2 (M=46)
38 – 30 = 8
\
/
19.2 = 38
/
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NO (M = 30)
46 – 38 = 8
$\Rightarrow \,\frac{{{n}_{N{{O}_{2}}}}}{{{n}_{NO}}}\,=\,\frac{8}{8}\,=\,1$
bảo toàn e có$3{{n}_{NO}}\,+\,{{n}_{N{{O}_{2}}}}\,=\,3{{n}_{Al}}\,=\,0,4\,\Rightarrow \,{{n}_{N{{O}_{2}}}}\,=\,0,75;\,{{n}_{NO}}\,=\,0,75$
$\Rightarrow \,{{n}_{HN{{O}_{3}}}}\,=\,{{n}_{NO}}\,+\,{{n}_{N{{O}_{2}}}}\,+\,3{{n}_{Al}}\,=\,4,5\,mol\,\Rightarrow \,{{C}_{M}}\,=\,4,5$