Đáp án đúng: C
6,4.
Trong dung dịch có 0,3 mol Fe3+, 0,075 mol Cu2+, 0,2 mol H+ và 0,625 mol $\text{SO}_{\text{4}}^{\text{2-}}$.
Tại Anot:
$\begin{array}{l}\text{2}{{\text{H}}_{\text{2}}}\text{O}\xrightarrow{{}}{{\text{O}}_{\text{2}}}\text{+4}{{\text{H}}^{\text{+}}}\text{+4e}\\{{\text{n}}_{e}}\text{=}\frac{\text{It}}{\text{F}}\text{=}\frac{\text{10}\text{.3860}}{\text{96500}}\text{=0,4}\,\text{mol}\Rightarrow {{\text{n}}_{{{\text{O}}_{\text{2}}}}}\text{=0,1}\,\text{mol}\end{array}$
Tại Katot:
$\displaystyle \begin{array}{l}\text{F}{{\text{e}}^{\text{3+}}}\text{+1e}\xrightarrow{{}}\text{F}{{\text{e}}^{\text{2+}}}\\\text{0,3}\,\to \,\text{0,3}\\\text{C}{{\text{u}}^{\text{2+}}}\text{+}\,\,\,\,\text{2e}\xrightarrow{{}}\text{Cu}\\\text{0,05}\leftarrow \text{0,1}\,\,\,\,\to \,\,\,\,\text{0,05}\end{array}$
Khối lượng dung dịch giảm là${{\text{m}}_{\text{Cu}}}\text{+}{{\text{m}}_{{{\text{O}}_{\text{2}}}}}\text{=0,05}\text{.64+0,1}\text{.32=6,4}\,\text{gam}$