Đáp án đúng: D TXĐ: D = R. $\begin{array}{l}y'=-{{x}^{3}}+x\\y'=0\Leftrightarrow -{{x}^{3}}+x=0\Leftrightarrow \left[ \begin{array}{l}x=0\\x=\pm 1\end{array} \right.\Rightarrow \left[ \begin{array}{l}y=-3\\y=-\frac{{11}}{4}\end{array} \right.\end{array}$.