Đáp án đúng: B $ \left\{ \begin{array}{l} & {{\text W }_ d }=\dfrac{1}{2} m{ v ^ 2 } \\ & p=mv \\ \end{array} \right.\Rightarrow {{\text W }_ d }=\dfrac{{ m ^ 2 }{ v ^ 2 }}{2m}=\dfrac{{ p ^ 2 }}{2m}\Rightarrow p=\sqrt{2m{{\text W }_ d }}=\sqrt{2.2.25}=10kg.m/s $