Đáp án:
Giải thích các bước giải: Bài 1:
$(3x+1)(\frac{1}{3}(3x-2))+5(3x+1)=2(2x+1)(\frac{1}{3}(3x+1))+2x(3x+1)\\\Leftrightarrow 9x^2+42x+13=30x^2+16x+2\\\Leftrightarrow 21x^2-26x-11=0\\\Leftrightarrow (3x+1)(7x-11)=0\\\Leftrightarrow \left[\begin{array}{l}x=-\frac{1}{3}\\x=\frac{11}{7}\end{array}\right.$
Bài 2:
$5+\frac{96}{x^2}-16=2x-\frac{1}{x}+4-3x-\frac{1}{4}-x\\\Leftrightarrow 8x^3-59x^2+4x+384=0\\\Leftrightarrow \left[\begin{array}{l}x=5,921772968\\x=-2,211693438\\x=3,66492047\end{array}\right.$