$ \dfrac{27-{{x}^{3}}}{5x+5}:\dfrac{2x-6}{3x+3}= $
A.$ -\dfrac{3\left( {{x}^{2}}+3x+9 \right)}{10} $
B.$ \dfrac{3\left( x+1 \right)}{10} $
C.$ -\dfrac{2\left( x-3 \right)}{15} $
D.$ \dfrac{{{x}^{2}}+3x+9}{10} $

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