a/
|a|=352⇔\(\left[ \begin{array}{l}a=352\\a=-352\end{array} \right.\)
b/
|3a+5|=537
⇔\(\left[ \begin{array}{l}3a+5=537\\3a+5=-537\end{array} \right.\) ⇔\(\left[ \begin{array}{l}3a=532\\3a=-542\end{array} \right.\) ⇔\(\left[ \begin{array}{l}a=\frac{532}{3} \\a=\frac{-524 }{3}\end{array} \right.\)
vậy a ∈ {$\frac{532}{3}$ ; $\frac{-524}{3}$ }
c/
15|2a-17|=225
⇔|2a-17|=225:15
⇔|2a-17|=15
⇔\(\left[ \begin{array}{l}2a-17=15\\2a-17=-15\end{array} \right.\) ⇔ \(\left[ \begin{array}{l}2a=32\\2a=-32\end{array} \right.\) ⇔\(\left[ \begin{array}{l}a=14 \\a=-14\end{array} \right.\)
vậy a∈{14;-14}
*nhớ vote 5* và cảm ơn cho câu trả lời của thienhong06 nhé*
