Cho hàm số y =$\dfrac{{{x}^{2}}+x+1}{x-1}$. Vi phân của hàm số là:
A.$\text{d}y=\dfrac{2x+1}{{{(x-1)}^{2}}}\text{d}x$
B.$\text{d}y=-\dfrac{2x+1}{{{(x-1)}^{2}}}\text{d}x$
C.$\text{d}y=\dfrac{{{x}^{2}}-2x-2}{{{(x-1)}^{2}}}\text{d}x$
D.$\text{d}y=-\dfrac{{{x}^{2}}-2x-2}{{{(x-1)}^{2}}}\text{d}x$
A.$\text{d}y=\dfrac{2x+1}{{{(x-1)}^{2}}}\text{d}x$
B.$\text{d}y=-\dfrac{2x+1}{{{(x-1)}^{2}}}\text{d}x$
C.$\text{d}y=\dfrac{{{x}^{2}}-2x-2}{{{(x-1)}^{2}}}\text{d}x$
D.$\text{d}y=-\dfrac{{{x}^{2}}-2x-2}{{{(x-1)}^{2}}}\text{d}x$
Loga
Hóa Học lớp 12
