$m_{H_{2}SO_{4}} = 200.\frac{14,7}{100} = 29,4g$
Có $m_{dd sau pư} = 8 + 200 = 208g$
$\Rightarrow$ C%$H_{2}SO_{4} = \frac{29,4}{208}.100 \approx 14,1$
$n_{CuO} = \frac{8}{64 + 16} = 0,1 mol$
$\Rightarrow m_{CuSO_{4}} = 0,1.160 = 16g$
$\Rightarrow$ C%$CuSO_{4} = \frac{16}{208}.100 \approx 7,7$