Sắp xếp theo thứ tự giảm dần: $ \dfrac{59}{19}\,;\,\,\,3\dfrac{3}{19}\,\,;\,\dfrac{59}{14}\,;\,4\dfrac{3}{17} $ ta được:
A. $ \dfrac{59}{14}\,;\,4\dfrac{3}{17}\,;\,3\dfrac{3}{19}\,;\,\dfrac{59}{19}. $
B. $ \,\dfrac{59}{19}\,\,;3\dfrac{3}{19}\,;\,4\dfrac{3}{17}\,;\,\dfrac{59}{14}\,. $
C. $ \dfrac{59}{14}\,;\,4\dfrac{3}{17}\,;\,\dfrac{59}{19};3\dfrac{3}{19}\,. $
D. $ 4\dfrac{3}{17}\,;\dfrac{59}{14}\,;\,\,3\dfrac{3}{19}\,;\,\dfrac{59}{19}. $
A. $ \dfrac{59}{14}\,;\,4\dfrac{3}{17}\,;\,3\dfrac{3}{19}\,;\,\dfrac{59}{19}. $
B. $ \,\dfrac{59}{19}\,\,;3\dfrac{3}{19}\,;\,4\dfrac{3}{17}\,;\,\dfrac{59}{14}\,. $
C. $ \dfrac{59}{14}\,;\,4\dfrac{3}{17}\,;\,\dfrac{59}{19};3\dfrac{3}{19}\,. $
D. $ 4\dfrac{3}{17}\,;\dfrac{59}{14}\,;\,\,3\dfrac{3}{19}\,;\,\dfrac{59}{19}. $
Loga
Hóa Học lớp 12
