Đáp án:
Giải thích các bước giải:
\(\begin{array}{l}
C1:\\
a.2x - 3 = 6 - 3x\\
\to 5x = 9 \to x = \frac{9}{5}\\
b.DK:x \ne \pm 3\\
Pt \to x + 3 + 5{x^2} - 45 = 5{x^2} - 15x - x + 3\\
\to 17x = 45\\
\to x = \frac{{45}}{{17}}\left( {TM} \right)\\
c. \to \left[ \begin{array}{l}
x + 5 = 2x\\
x + 5 = - 2x
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = 5\\
x = \frac{{ - 5}}{3}
\end{array} \right.\\
C2:\\
6x - 10 > 4x - 6\\
\to 2x > 4\\
\to x > 2
\end{array}\)
