\(\begin{array}{l}
CO_3^{2-}+2H^+\to CO_2+H_2O\\
Ta\,co\,n_{CO_2}=n_{H_2O}=\frac{3,36}{22,4}=0,15(mol)\\
BTNT\,H:\,n_{HCl}=2n_{H_2O}=0,3(mol)\\
BTKL:\\
m_X+m_{HCl}=m_{muối}+m_{CO_2}+m_{H_2O}\\
\to m_{muối}=230+0,3.36,5-0,15.44-0,15.18=231,65(g)
\end{array}\)