Đáp án đúng: B Giải chi tiết:\(\begin{array}{l}\,\,\frac{7}{{19}}:\frac{2}{3} + \frac{{12}}{{19}}:\frac{2}{3}\\ = \left( {\frac{7}{{19}} + \frac{{12}}{{19}}} \right):\frac{2}{3}\\ = \,\,\,\,\,\,\,\frac{{19}}{{19}}:\frac{2}{3}\\ = 1:\frac{2}{3}\\ = \frac{3}{2}\end{array}\) Chọn B