$|x-7|+3=2x$
⇔ $|x-7| = 2x - 3$
⇔$\left \{ {{x-7=2x-3(đk: x-7≥0)} \atop {7-x=2x-3(đk:x-7<0)}} \right.$
⇔$\left \{ {{x-2x=-3+7(đk:x≥7)} \atop {-x-2x=-3-7(đk:x<7)}} \right.$
⇔$\left \{ {{-x=4(đk:x≥7)} \atop {-3x=-10(đk:x<7)}} \right.$
⇔$\left \{ {{x=-4(loại)} \atop {x=\frac{10}{3}(tm)}} \right.$
Vậy $S=$ $\frac{10}{3}$
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