*\(\dfrac{7}{4}.x+\dfrac{3}{2}=\dfrac{-2}{5}\)
\(\Rightarrow\dfrac{7}{4}.x=\dfrac{-2}{5}-\dfrac{3}{2}=\dfrac{-4}{10}-\dfrac{15}{10}=\dfrac{-19}{10}\)
\(\Rightarrow x=\dfrac{-19}{10}:\dfrac{7}{4}=\dfrac{-19}{10}.\dfrac{4}{7}=\dfrac{-38}{35}\)
*\(\left(5x-1\right)\left(2x-\dfrac{1}{3}\right)=0\Rightarrow5x-1=0\) hoặc \(2x-\dfrac{1}{3}=0\)
+Với \(5x-1=0\Rightarrow5x=0+1=1\)
_________________\(x=1:5=\dfrac{1}{5}\)
+Với \(2x-\dfrac{1}{3}=0\Rightarrow2x=0+\dfrac{1}{3}=\dfrac{1}{3}\)
_________________\(x=\dfrac{1}{3}:2=\dfrac{1}{3}.\dfrac{1}{2}=\dfrac{1}{6}\)