\(\begin{array}{l}
2Al + 6HCl \to 2AlC{l_3} + 3{H_2}\\
ZnO + 2HCl \to ZnC{l_2} + {H_2}\\
a)\\
n{H_2} = \dfrac{{13,44}}{{22,4}} = 0,6\,mol\\
= > nAl = 0,4\,mol\\
\% mAl = \dfrac{{0,4 \times 27}}{{27}} \times 100\% = 40\% \\
\% mZnO = 100 - 40 = 60\% \\
b)\\
nZnO = \dfrac{{27 \times 60\% }}{{81}} = 0,2\,mol\\
nHCl = 0,4 \times 3 + 0,2 \times 2 = 1,6\,mol\\
m{\rm{dd}}HCl = \dfrac{{1,6 \times 36,5}}{{29,2\% }} = 200g\\
c)\\
m{\rm{dd}}spu = 27 + 200 - 0,6 \times 2 = 225,8g\\
C\% AlC{l_3} = \dfrac{{0,4 \times 133,5}}{{225,8}} \times 100\% = 23,65\% \\
C\% ZnC{l_2} = \dfrac{{0,2 \times 136}}{{225,8}} \times 100\% = 12,05\%
\end{array}\)