7/8x+ (5 - x)/(4x^2 - 8x) = (x - 1)/2x(x - 2) + 1/(8x - 16)
ĐKXĐ: x ≠ 0; x ≠ 2
⇔ 7/(8x)-1/[8(x-2)]=( x-5)/[4x(x - 2)] +(x - 1)/[2x(x - 2) ]
⇔ [7(x-2)-x]/[8x.(x-2)]=[( x-5)+2(x - 1)]/[4x(x - 2) ]
⇔ (6x-14)/[8x.(x-2)]=(3x-7)/[4x(x - 2) ]
⇔ (3x-7)/[4x.(x-2)]=(3x-7)/[4x(x - 2)
Vậy x€R\{0,2}