$n_{Mg}=12/24=0,5mol$
$a/$
$PTHH:$
$2Mg+O2\overset{t^o}{\rightarrow}2MgO$
$ b/$
Theo pt:
$n_{O2}=1/2.n_{Mg}=1/2.0,5=0,25mol$
$⇒V_{O2}=0,25.22,5=5,6l$
$c/$
Theo pt:
$n_{MgO}=n_{Mg}=0,5mol$
$⇒m_{MgO}=0,5.40=20g$
$d/$
$n_{Mg}=12/24=0,5mol$
$a/$
$PTHH:$
$2Mg+O2\overset{t^o}{\rightarrow}2MgO$
$ b/$
Theo pt:
$n_{O2}=1/2.n_{Mg}=1/2.0,5=0,25mol$
$⇒V_{O2}=0,25.22,5=5,6l$
$c/$
Theo pt:
$n_{MgO}=n_{Mg}=0,5mol$
$⇒m_{MgO}=0,5.40=20g$
$d/$
$n_{O2}=11,2/22,4=0,5mol$
$⇒KL$ $MgO$ tăng