Giải thích các bước giải:
a.Ta có :
$1=a.2\to a=\dfrac 12\to y=\dfrac 12x$
$\to \dfrac{y_0-2}{x_0-4}=\dfrac{\dfrac 12x_0-2}{x_0-4}=\dfrac{\dfrac 12(x_0-4)}{x_0-4}=\dfrac 12$
b.Do $x_0=5\to y_0=\dfrac 12.5=\dfrac 52$
$\to S_{OBC}=\dfrac 12 CB.CO=\dfrac 12 y_0x_0=\dfrac{25}4$