Đáp án:
Giải thích các bước giải:
a) $18x^2(x+4)-12(x^2+4x)=0\\\Leftrightarrow 18x^3+60x^2-48x=0\\\Leftrightarrow x(3x-2)(x+4)=0\\\Leftrightarrow \left[\begin{array}{l}x=0\\x=\frac{2}{3}\\x=-4\end{array}\right.$
b) $3x^2-6x+3=(x-1)(4x-5)\\\Leftrightarrow 3x^2-6x+3-(x-1)(4x-5)=0\\\Leftrightarrow x^2-3x+2=0\\\Leftrightarrow (x-1)(x-2)=0\\\Leftrightarrow \left[\begin{array}{l}x=1\\x=2\end{array}\right.$