Hình bên vẽ đồ thị các hàm số \(f\left( x \right) = - {x^2} - 2x + 1\) và \(g\left( x \right) = - \dfrac{1}{2}{x^3} - \dfrac{5}{2}{x^2} - \dfrac{3}{2}x + \dfrac{5}{2}\). Diện tích phần gạch chép trong hình bằng
A.\(\int\limits_{ - 3}^{ - 1} {\left[ {f\left( x \right) - g\left( x \right)} \right]} \,dx + \int\limits_{ - 1}^1 {\left[ {g\left( x \right) - f\left( x \right)} \right]} \,dx\)
B.\(\int\limits_{ - 3}^{ - 1} {\left[ {g\left( x \right) - f\left( x \right)} \right]} \,dx + \int\limits_{ - 1}^1 {\left[ {f\left( x \right) - g\left( x \right)} \right]} \,dx\)
C.\(\int\limits_{ - 3}^{ - 1} {\left[ {f\left( x \right) - g\left( x \right)} \right]} \,dx + \int\limits_{ - 1}^1 {\left[ {f\left( x \right) - g\left( x \right)} \right]} \,dx\)
D.\(\int\limits_{ - 3}^{ - 1} {\left[ {g\left( x \right) - f\left( x \right)} \right]} \,dx + \int\limits_{ - 1}^1 {\left[ {g\left( x \right) - f\left( x \right)} \right]} \,dx\)
A.\(\int\limits_{ - 3}^{ - 1} {\left[ {f\left( x \right) - g\left( x \right)} \right]} \,dx + \int\limits_{ - 1}^1 {\left[ {g\left( x \right) - f\left( x \right)} \right]} \,dx\)
B.\(\int\limits_{ - 3}^{ - 1} {\left[ {g\left( x \right) - f\left( x \right)} \right]} \,dx + \int\limits_{ - 1}^1 {\left[ {f\left( x \right) - g\left( x \right)} \right]} \,dx\)
C.\(\int\limits_{ - 3}^{ - 1} {\left[ {f\left( x \right) - g\left( x \right)} \right]} \,dx + \int\limits_{ - 1}^1 {\left[ {f\left( x \right) - g\left( x \right)} \right]} \,dx\)
D.\(\int\limits_{ - 3}^{ - 1} {\left[ {g\left( x \right) - f\left( x \right)} \right]} \,dx + \int\limits_{ - 1}^1 {\left[ {g\left( x \right) - f\left( x \right)} \right]} \,dx\)
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