1)
a)
MnO2+4HCl->MnCl2+Cl2+2H2O
Cl2+2NaOH->NaCl+NaClO+H2O
nCl2=nMnO2=69,6/87=0,8 mol
nNaOH=0,5x4=2 mol
=>nNaOH=2-0,8x2=0,4 mol
CMNaOH=0,4/0,5=0,8M
CMNaCl=CMNaCl=0,8/0,5=1,6 M
c)
6KOH+3Cl2->5KCl+KClO3+3H2O
0,8 0,8/3
mKClO3=0,8/3x122,5=32,67 g
Bài 2
2M+6HCl->2MCl3+3H2
nHCl tham gia=0,2-0,08=0,12 mol
=>nM=0,12x2/6=0,04 mol
=>MM=1,08/0,04=27 g/mol
=> M là Al
V=0,06x22,4=1,344 l