Giải thích các bước giải:
Ta có :
$\dfrac{12x+1}{11x-4}+\dfrac{10x-4}{9}=\dfrac{20x+17}{18}$
$\to \dfrac{12x+1}{11x-4}=\dfrac{20x+17}{18}-\dfrac{10x-4}{9}$
$\to \dfrac{12x+1}{11x-4}=\dfrac{20x+17}{18}-\dfrac{2(10x-4)}{18}$
$\to \dfrac{12x+1}{11x-4}=\dfrac{20x+17}{18}-\dfrac{20x-8}{18}$
$\to \dfrac{12x+1}{11x-4}=\dfrac{20x+17-(20x-8)}{18}$
$\to \dfrac{12x+1}{11x-4}=\dfrac{20x+17-20x+8}{18}$
$\to \dfrac{12x+1}{11x-4}=\dfrac{25}{18}$
$\to 18(12x+1)=25(11x-4)$
$\to 216x+18=275x-100$
$\to 59x=118$
$\to x=2$