$\frac{5}{6}$ - ║$\frac{1}{6}$ -x ║=0
⇒ |$\frac{1}{6}$ -x| = $\frac{5}{6}$
⇒ \(\left[ \begin{array}{l}\frac{1}{6} -x=\frac{5}{6}\\{1}{6} -x=\frac{-5}{6}\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=\frac{-2}{3}\\x=1\end{array} \right.\)
Vậy x ∈ { $\frac{2}{3}$ ; 1}