10-2(x+1)²=2
2(x+1)²=10-2
2(x+1)²=8
(x+1)²=8:2
(x+1)²=4
(x+1)²=(±2)²
\(\left[ \begin{array}{l}x+1=2\\x+1=-2\end{array} \right.\)
\(\left[ \begin{array}{l}x=2-1\\x=-2-1\end{array} \right.\)
\(\left[ \begin{array}{l}x=1\\x=-3\end{array} \right.\)
Vậy x∈{1,-3}