ta có : \(x^{2017}=x\Leftrightarrow x^{2017}-x=0\Leftrightarrow x\left(x^{2016}-1\right)=0\)
\(\left\{{}\begin{matrix}x=0\\\left(x^{2016}-1\right)=0\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=0\\\left\{{}\begin{matrix}x=1\\x=-1\end{matrix}\right.\end{matrix}\right.\) vậy \(x=0;x=1;x=-1\)
