Đáp án:c)$x=\frac{42}{11}$
d) x=-1
e)x$=\frac{-11}{6}$
Giải thích các bước giải:
c)$\frac{1}{2}x+\frac{3}{5}(x-2)=3$
<=>$\frac{1}{2}x+\frac{3}{5}x-\frac{6}{5}=3$
<=>$\frac{11}{10}x=\frac{21}{3}$
<=> $x=\frac{42}{11}$
d)$\frac{11}{12}x+\frac{3}{4}=-\frac{1}{6}$
<=>$\frac{11}{12}=\frac{-1}{6}-\frac{3}{4}$
<=>$\frac{11}{12}x=\frac{-11}{12}$
<=>x=-1
e)$3-(\frac{1}{6}-x)\frac{2}{3}x=\frac{2}{3}$
<=>$3-(\frac{1}{6}-x)=1$
<=> $\frac{1}{6}-x=2 <=> x=\frac{-11}{6}$
