\(4{x^2} - {y^2} + 8\left( {y - 2} \right)\)
A.\(4{x^2} - {y^2} + 8\left( {y - 2} \right) = \left( {2x + y - 4} \right)\left( {2x - y + 4} \right)\).
B.\(4{x^2} - {y^2} + 8\left( {y - 2} \right) = \left( {2x + y - 4} \right)\left( {2x + y - 4} \right)\).
C.\(4{x^2} - {y^2} + 8\left( {y - 2} \right) = \left( {2x + y - 4} \right)\left( {2x - y - 4} \right)\).
D.\(4{x^2} - {y^2} + 8\left( {y - 2} \right) = \left( {x + 2y - 4} \right)\left( {x - 2y + 4} \right)\).
A.\(4{x^2} - {y^2} + 8\left( {y - 2} \right) = \left( {2x + y - 4} \right)\left( {2x - y + 4} \right)\).
B.\(4{x^2} - {y^2} + 8\left( {y - 2} \right) = \left( {2x + y - 4} \right)\left( {2x + y - 4} \right)\).
C.\(4{x^2} - {y^2} + 8\left( {y - 2} \right) = \left( {2x + y - 4} \right)\left( {2x - y - 4} \right)\).
D.\(4{x^2} - {y^2} + 8\left( {y - 2} \right) = \left( {x + 2y - 4} \right)\left( {x - 2y + 4} \right)\).
Loga
Hóa Học lớp 12
