Cho các phân thức \(\dfrac{{3x - 2}}{{{x^2} + 2x - 3}};\,\,\dfrac{{2x - 1}}{{{x^2} + 7x + 12}}\). Phân thức \(\dfrac{{3x - 2}}{{{x^2} + 2x - 3}}\) sau khi quy đồng mẫu là
A.\(\dfrac{{\left( {3x - 2} \right)\left( {x + 4} \right)}}{{\left( {x - 1} \right)\left( {x + 3} \right)\left( {x + 4} \right)}}\)
B.\(\dfrac{{3x - 2}}{{\left( {x - 1} \right)\left( {x + 3} \right)\left( {x + 4} \right)}}\)
C.\(\dfrac{{\left( {3x - 2} \right)\left( {x + 4} \right)}}{{\left( {x - 1} \right){{\left( {x + 3} \right)}^2}\left( {x + 4} \right)}}\)
D.\(\dfrac{{3x - 2}}{{\left( {x - 1} \right)\left( {x + 3} \right)}}\)
A.\(\dfrac{{\left( {3x - 2} \right)\left( {x + 4} \right)}}{{\left( {x - 1} \right)\left( {x + 3} \right)\left( {x + 4} \right)}}\)
B.\(\dfrac{{3x - 2}}{{\left( {x - 1} \right)\left( {x + 3} \right)\left( {x + 4} \right)}}\)
C.\(\dfrac{{\left( {3x - 2} \right)\left( {x + 4} \right)}}{{\left( {x - 1} \right){{\left( {x + 3} \right)}^2}\left( {x + 4} \right)}}\)
D.\(\dfrac{{3x - 2}}{{\left( {x - 1} \right)\left( {x + 3} \right)}}\)
Loga
Hóa Học lớp 12
