Giải thích các bước giải:
Ta có :
$\dfrac{ab}{a+b}=\dfrac{bc}{b+c}=\dfrac{ca}{c+a}$
$\to\dfrac{a+b}{ab}=\dfrac{b+c}{bc}=\dfrac{c+a}{ca}$
$\to\dfrac{1}{a}+\dfrac 1b=\dfrac 1b+\dfrac 1c=\dfrac 1c+\dfrac 1a$
$\to \begin{cases}\dfrac 1a=\dfrac 1c\\\dfrac 1b=\dfrac 1c\end{cases}$
$\to a=b=c$
$\to M=\dfrac{3a^2}{3a^2}=1$