A.\(\dfrac{{x - 1}}{1} = \dfrac{{y + 1}}{2} = \dfrac{{z + 2}}{{ - 1}}\) B.\(\dfrac{{x - 1}}{{ - 1}} = \dfrac{{y - 2}}{1} = \dfrac{{z + 1}}{2}\)C.\(\dfrac{{x + 1}}{1} = \dfrac{{y - 1}}{2} = \dfrac{{z - 2}}{{ - 1}}\) D.\(\dfrac{{x + 1}}{{ - 1}} = \dfrac{{y + 1}}{1} = \dfrac{{z - 1}}{2}\)
A.\(M\left( {0;1;2} \right)\)B.\(N\left( {2;0;1} \right)\) C.\(P\left( {0;0;1} \right)\)D.\(Q\left( {2;1;0} \right)\)
A.\(L = - 5\)B.\(L = 5\)C.\(L = 0\)D.\(L = - 3\)
A.\(I = - \dfrac{{21}}{{100}}\)B.\(I = \ln \dfrac{5}{2}\) C.\(I = \dfrac{{4581}}{{5000}}\) D.\(I = \log \dfrac{5}{2}\)
A.\({\log _a}b < 0\)B.\(\ln a > \ln b\) C.\({\left( {0,5} \right)^a} < {\left( {0,5} \right)^b}\) D.\({2^a} > {2^b}\)
A.\(y = {\log _3}x\)B.\(y = \dfrac{1}{{{3^x}}}\) C.\(y = \dfrac{1}{{1 + x}}\) D.\(x = {\left( {\sqrt 3 } \right)^x}\)
A.2B.0C.1D.3
A.\(y = {x^3} - 5{x^2} + x + 6\)B.\(y = {x^3} - 6{x^2} + 9x - 1\)C.\(y = - {x^3} + 6{x^2} - 9x + 7\)D.\(y = {x^4} + {x^2} - 3\)
A.\(16\)B.\(4 + 2\sqrt 3 \) C.\(12\)D.\(20\)
A.\(9\pi \sqrt 3 \) B.\(27\pi \sqrt 3 \) C.\(3\pi \sqrt 3 \) D.\(6\pi \sqrt 3 \)
Loga.vn - Cộng Đồng Luyện Thi Trực Tuyến