A.\(\left| {\dfrac{{\sin 2\alpha }}{{2m}}} \right| = 2\left| m \right|\sqrt {1 - {m^2}} \)
B.\(\left| {\dfrac{{\sin 2\alpha }}{{2m}}} \right| = 2\sqrt {1 - {m^2}} \)
C.\(\left| {\dfrac{{\sin 2\alpha }}{{2m}}} \right| = \sqrt {1 - {m^2}} \)
D.\(\left| {\dfrac{{\sin 2\alpha }}{{2m}}} \right| = 2\left| m \right|\left| {1 - {m^2}} \right|\)