A.\(x \in \left\{ {\dfrac{4}{3};\,\,2} \right\}\)
B.\(x \in \left\{ { - \dfrac{4}{3};\,\, - 2} \right\}\)
C.\(x \in \left\{ { - \dfrac{4}{3};\,\,2} \right\}\)
D.\(x \in \left\{ {\dfrac{4}{3};\,\, - 2} \right\}\)

A.\(x = 1\)
B.\(x = \dfrac{5}{6}\)
C.\(x = \dfrac{6}{5}\)
D.\(x = 0\)

A.\(x =  - \dfrac{1}{2}\)
B.\(x =  - \dfrac{2}{3}\)
C.\(x =  - \dfrac{1}{3}\)
D.\(x =  - \dfrac{1}{4}\)

A.\(x =  - \dfrac{5}{4}\)
B.\(x =  - 1\)
C.\(x =  - \dfrac{3}{4}\)
D.\(x =  - \dfrac{4}{3}\)

A.\(x =  - \dfrac{5}{4}\)
B.\(x =  - 1\)
C.\(x =  - \dfrac{3}{4}\)
D.\(x =  - \dfrac{4}{3}\)

A.\( - 6\)
B.\( - 4\)
C.\( - 7\)
D.\( - 8\)

A.\( - 2\)
B.\( - \dfrac{5}{2}\)
C.\( - \dfrac{7}{2}\)
D.\( - \dfrac{3}{2}\)

A.decided
B.installed
C.visited
D.appointed

A.\(2\dfrac{2}{5}\)
B.\(2\dfrac{1}{5}\)
C.\(2\dfrac{4}{5}\)
D.\(2\dfrac{3}{5}\)

A.\(y =  - \dfrac{{11}}{5}\)
B.\(y =  - \dfrac{{23}}{{10}}\)
C.\(y =  - 1\)
D.\(y =  - \dfrac{{13}}{{10}}\)