ĐK:x≥0
$2\sqrt[]{8x} +7\sqrt[]{18x} =9-\sqrt[]{50x}$
⇔$2\sqrt[]{8x} +7\sqrt[]{18x}+\sqrt[]{50x} =9$
⇔$x(2\sqrt[]{8}+7\sqrt[]{18}+\sqrt[]{50})=9$
⇔$\sqrt[]{30}.x=9$
⇔$x=\frac{9}{30\sqrt[]{2}}=\frac{3\sqrt[]{2}}{20}$ (TM)
Vậy $x=\frac{3\sqrt[]{2}}{20}$