a,
KOH+ HCl -> KCl+ H2O
nHCl= 1,5.0,25= 0,375 mol= nKOH= nKCl
=> V KOH= $\frac{0,375}{2}$= 0,1875l= 187,5ml
b, (không tính đc C% nên mình chuyển sang CM)
CM KCl= $\frac{0,375}{0,1875+0,25}$= 0,86M
c, NaOH+ HCl -> NaCl+ H2O
=> nNaOH= 0,375 mol
=> mdd NaOH= $\frac{0,375.40.100}{10}$= 150g