Câu 2 :
a) $11x^{3y}$$^{2}$
b)A= $5x^{3y}$$^{4}$ - $\frac{x}{y}$$3x^{3y}$$^{4}$
Giải thích các bước giải:
a) C+D= $8x^{3y}$$^{4}$ - $\frac{1}{3x}$$^{3y}$$^{4}$ + $3x^{3y}$$^{4}$ + $\frac{1}{3x}$$^{3y}$$^{4}$
= $11x^{3y}$$^{2}$
b) C-A=D
=> A= C-D
= $8x^{3y}$$^{4}$ - $\frac{1}{3x}$$^{3y}$$^{4}$ + $3x^{3y}$$^{4}$ + $\frac{1}{3x}$$^{3y}$$^{4}$
=$5x^{3y}$$^{4}$ - $\frac{x}{y}$$3x^{3y}$$^{4}$
