Đáp án:
\[ - \frac{{348}}{{65}}\]
Giải thích các bước giải:
Ta có:
\(\begin{array}{l}
\frac{{{{\left( { - 2} \right)}^3}.\left( {\frac{3}{4} - 0,025} \right)}}{{2\frac{1}{4} - 1\frac{1}{6}}}\\
= \frac{{\left( { - 8} \right).\left( {\frac{3}{4} - \frac{{25}}{{1000}}} \right)}}{{\frac{{2.4 + 1}}{4} - \frac{{6.1 + 1}}{6}}}\\
= \frac{{\left( { - 8} \right).\left( {\frac{3}{4} - \frac{1}{{40}}} \right)}}{{\frac{9}{4} - \frac{7}{6}}}\\
= \frac{{\left( { - 8} \right).\frac{1}{4}.\left( {3 - \frac{1}{{10}}} \right)}}{{\frac{{9.3 - 7.2}}{{12}}}}\\
= \frac{{\left( { - 2} \right).\frac{{3.10 - 1}}{{10}}}}{{\frac{{13}}{{12}}}}\\
= \frac{{ - 29}}{5}:\frac{{13}}{{12}}\\
= - \frac{{348}}{{65}}
\end{array}\)
