Giải thích các bước giải:
$|x+2|+|x-2|-3|x+4|\ge 2$
$+)x<-4$
$\to -\left(x+2\right)-\left(x-2\right)-3\left(-\left(x+4\right)\right)\ge \:2$
$\to x\ge \:-10\to -10\le x<-4$
$+)-4\le \:x<-2$
$\to -\left(x+2\right)-\left(x-2\right)-3\left(x+4\right)\ge \:2$
$\to x\le -\dfrac{14}{5}\to -4\le x\le -\dfrac{14}{5}$
$+) -2\le x<2\to x+2-\left(x-2\right)-3\left(x+4\right)\ge \:2$
$\to x\le -\dfrac{10}{3}\to$ loại
$+)x\ge 2\to x+2+x-2-3\left(x+4\right)\ge \:2$
$\to x\le -14\to$ loại
$\to -10\le x\le -\dfrac{14}{5}$
