\(5x\left(x-3\right)+4x-12=0\)
\(\Leftrightarrow5x\left(x-3\right)+4\left(x-3\right)=0\)
\(\Leftrightarrow\left(x-3\right)+\left(5x+4\right)=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}x-3=0\\5x+4=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=3\\x=-0,8\end{matrix}\right.\)
Vậy :\(x\in\left\{3;-0,8\right\}\)