Lời giải:
a, Ta có: `1234 = 2 xx 617` ; `6532 = 2^2 xx 23 xx 71`
b, +) Ta có: `ƯCLN (1234, 6532) = 2` `⇒ ƯC (1234, 6532) = Ư (2) = { ±1 ; ±2 }`
+) `BCNN (1234, 6532) = 2^2 xx 23 xx 71 xx 617 = 4030244`
`⇒ BC (1234, 6532) = B (4030244) = { 0 ; ±4030244 ; ±8060488 ; ... }`
c, Ta có: `1234 = 2 xx 617` `-> 1234` có `2 xx 2 = 4` (ước)
`6532 = 2^2 xx 23 xx 71` `-> 6532` có `3 xx 2 xx 2 = 12` (ước)
d, Ta có:
`BCNN (1234, 6532) : ƯCLN (1234, 6532) = 4030244 : 2 = 2015122`